(2^x)+(2^-x)=17/4

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Solution for (2^x)+(2^-x)=17/4 equation: 



(2^x)+(2^-x)=17/4

We move all terms to the left:

(2^x)+(2^-x)-(17/4)=0

We add all the numbers together, and all the variables

2^x+(2^-x)-(+17/4)=0

We get rid of parentheses

2^x-x+2^-17/4=0

We multiply all the terms by the denominator


2^x*4-x*4-17+2^*4=0

We add all the numbers together, and all the variables

2^x*4-x*4=0

Wy multiply elements

8x-4x=0

We add all the numbers together, and all the variables

4x=0

x=0/4

x=0

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